A common way to interpret ODFs is to think of them as superposition of different components that originate from different deformation processes and describe the texture of the material. In this section we describe how these components can be identified from a given ODF.
We start by reconstruction a Quartz ODF from Neutron pole figure data.
% import Neutron pole figure data from a Quartz specimen
plottingConvention.default("y↑→x");
mtexdata dubna silent
% reconstruct the ODF
odf = calcODF(pf,'zeroRange');
% visualize the ODF in sigma sections
plotSection(odf,'sigma','sections',12,'layout',[3,4])
mtexColorbar
The preferred orientation
First of all we observe that the ODF posses a strong maximum. To find this orientation that corresponds to the maximum ODF intensity we use the max command.
[value,ori] = max(odf)value =
110.3994
ori = orientation (Quartz → y↑→x)
Bunge Euler angles in degree
phi1 Phi phi2
133.758 34.4328 206.931Note that, similarly as the MATLAB max command, the second output argument is the position where the maximum is attained. In our case we observe that the maximum value is about 121. To visualize the corresponding preferred orientation we plot it into the sigma sections of the ODF.
annotate(ori)
We may not only use the command max to find the global maximum of an ODF but also to find a certain amount of local maxima. The number of local maxima MTEX should search for, is specified as by the option 'numLocal', i.e., to find the three largest local maxima do
[value,ori] = max(odf,'numLocal',3)
annotate(ori(2:end),'MarkerFaceColor','red')value =
110.3994
47.2245
31.9077
ori = orientation (Quartz → y↑→x)
size: 3 x 1
Bunge Euler angles in degree
phi1 Phi phi2
133.758 34.4328 206.931
136.719 36.8778 262.522
70.252 31.5819 284.547
Note, that orientations are returned sorted according to their ODF value.
Volume Portions
It is important to understand, that the value of the ODF at a preferred orientation is in general not sufficient to judge the importance of a component. Very sharp components may result in extremely large ODF values that represent only very little volume. A more robust and physically more relevant quantity is the relative volume of crystal that have an orientation close to the preferred orientation. This volume portion can be computed by the command volume(odf,ori,delta) where ori is a list of preferred orientations and delta is the maximum disorientation angle. Multiplying with \(100\) the output will be in percent
delta = 10*degree;
volume(odf,ori,delta) * 100ans =
11.3229
5.1668
4.0250We observe that the sum of all volume portions is far from \(100\) percent. This is very typical. The reason is that the portion of the full orientations space that is within the \(10\) degree disorientation distance from the preferred orientations is very small. More precisely, it represents only
volume(uniformODF(odf.CS),ori(1),delta) * 100ans =
0.1690percent of the entire orientations space. Putting these values in relation it becomes clear, that all the components are multiple times stronger than the uniform distribution. We may compute these factors by
volume(odf,ori,delta) ./ volume(uniformODF(odf.CS),ori,delta)ans =
67.0094
30.5774
23.8202It is important to understand, that all these values above depend significantly from the chosen disorientation angle delta. If delta is chosen too large
delta = 40*degree
volume(odf,ori,delta)*100delta =
0.6981
ans =
58.7745
35.2044
43.0778it may even happen that the components overlap and the sum of the volumes exceeds 100 percent.
Non circular components
A disadvantage of the approach above is that one is restricted to circular components with a fixed disorientation angle which makes it hard to analyze components that are close together. In such settings one may want to use the command calcComponents. This command starts with evenly distributed orientations and lets the crawl towards the closest preferred orientation. At the end of this process the command returns these preferred orientation and the percentage of orientations that crawled to each of them.
[ori, vol] = calcComponents(odf);
ori
vol * 100ori = orientation (Quartz → y↑→x)
size: 4 x 1
Bunge Euler angles in degree
phi1 Phi phi2
133.849 34.3839 206.936
136.563 36.7422 143.218
70.3299 31.2769 284.594
82.2988 29.9465 331.104
ans =
48.4320
22.0545
21.3252
7.2784These volumes always sums up to approximately 100 percent. While the preferred orientations should be the same as those computed by the max command.
annotate(ori,'MarkerFaceColor','none','MarkerEdgeColor','white',...
'linewidth',2,'MarkerSize',15,'marker','o')