Here we discuss tools for the analysis of EBSD data which are independent of its spatial coordinates. For spatial analysis, we refer to this page.

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Data import |

Orientation plot |

Let us first import some EBSD data:

plotx2east ebsd = loadEBSD(fullfile(mtexDataPath,'EBSD','Forsterite.ctf'),... 'convertEuler2SpatialReferenceFrame'); plot(ebsd)

We start our investigations of the Forsterite phase by plotting some pole figures

cs = ebsd('Forsterite').CS % the crystal symmetry of the forsterite phase h = [Miller(1,0,0,cs),Miller(0,1,0,cs),Miller(0,0,1,cs)]; plotPDF(ebsd('Forsterite').orientations,h,'antipodal')

cs = crystalSymmetry mineral : Forsterite color : light blue symmetry: mmm a, b, c : 4.8, 10, 6 I'm plotting 1250 random orientations out of 152345 given orientations You can specify the the number points by the option "points". The option "all" ensures that all data are plotted

From the {100} pole figure, we might suspect a fibre texture present in our data. Let's check this. First, we determine the vector orthogonal to fibre in the {100} pole figure

% the orientations of the Forsterite phase ori = ebsd('Forsterite').orientations % the vectors in the 100 pole figure r = ori * Miller(1,0,0,ori.CS) % the vector best orthogonal to all r rOrth = perp(r) % output hold on plot(rOrth) hold off

ori = orientation size: 152345 x 1 crystal symmetry : Forsterite (mmm) specimen symmetry: 1 r = vector3d size: 152345 x 1 rOrth = vector3d size: 1 x 1 x y z -0.944141 0.189955 -0.269287

we can check how large is the number of orientations that are in the (100) polegigure within a 10-degree fibre around the
great circle with center `rOrth`. The following line gives the result in percent

100 * sum(angle(r,rOrth)>80*degree) / length(ori)

ans = 78.7732

Next, we want to answer the question which crystal direction is mapped to `rOrth`. To this end, we look at the corresponding inverse pole figure

plotIPDF(ebsd('Forsterite').orientations,rOrth,'smooth') mtexColorbar %From the inverse pole figure, it becomes clear that the orientations are % close to the fibre |Miller(0,1,0)|, |rOrth|. Let's check this by computing % the fibre volume in percent % define the fibre f = fibre(Miller(0,1,0,cs),rOrth); % compute the volume along the fibre 100 * volume(ebsd('Forsterite').orientations,f,10*degree)

e = PropertyEvent with properties: AffectedObject: [1×1 ColorBar] Source: [1×1 matlab.graphics.internal.GraphicsMetaProperty] EventName: 'PostSet' ans = 27.9806

Surprisingly this value is significantly lower than the value we obtained we looking only at the 100 pole figure. Finally, let's plot the ODF along this fibre

odf = calcODF(ebsd('Forsterite').orientations) % plot the odf along the fibre plot(odf,f) ylim([0,26])

odf = ODF crystal symmetry : Forsterite (mmm) specimen symmetry: 1 Harmonic portion: degree: 28 weight: 1

We see that to ODF is far from beeing constant along the fibre. Thus, together with an observation about the small fibre volume, we would reject the hypothesis of a fibre texture.

Let's finally plot the ODF in orientation space to verify our decision

`plot(odf,'sigma')`

Here we see the typical large individual spots that are typical for large grains. Thus the ODF estimated from the EBSD data and all our previous analysis suffer from the fact that too few grains have been measured. For texture analysis, it would have been favorable to measure at a lower resolution but a larger region.

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